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    filter_has_var

    (PHP 5 >= 5.2.0, PHP 7, PHP 8)

    filter_has_var — 指定した型の変数が存在するかどうかを調べる

    説明

    filter_has_var(int $input_type, string $var_name): bool

    パラメータ

    input_type

    INPUT_GET、INPUT_POST、 INPUT_COOKIE、INPUT_SERVER、 INPUT_ENV のいずれか。

    var_name

    調べたい変数の名前。

    戻り値

    成功した場合に true を、失敗した場合に false を返します。

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    User Contributed Notes 2 notes

    up
    33
    drm at melp dot nl
    15 years ago
    Please note that the function does not check the live array, it actually checks the content received by php:

    <?php
    $_GET    ['test'] = 1;
    echo     filter_has_var(INPUT_GET, 'test') ? 'Yes' : 'No';
    ?>

    would say "No", unless the parameter was actually in the querystring.

    Also, if the input var is empty, it will say Yes.
    up
    19
    nanhe dot kumar at gmail dot com
    11 years ago
    Through this example i think you can better understand

    if ( !filter_has_var(INPUT_GET, 'email') ) {
    echo "Email Not Found";
    }else{
    echo "Email Found";
    }
    Output

    localhost/nanhe/test.php?email=1 //Email Found
    localhost/nanhe/test.php?email //Email Found
    http://localhost/nanhe/test.php //Email Not Found

    Consider on second example

    http://localhost/nanhe/test.php
    $_GET['email']="info@nanhe.in";
    if ( !filter_has_var(INPUT_GET, 'email') ) {
    echo "Email Not Found";
    }else{
    echo "Email Found";
    }
    But output will be Email Not Found
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