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    ArrayIterator::next

    (PHP 5, PHP 7, PHP 8)

    ArrayIterator::next — 次のエントリに移動する

    説明

    public ArrayIterator::next(): void

    この関数は次のエントリにイテレータを移動します。

    パラメータ

    この関数にはパラメータはありません。

    戻り値

    値を返しません。

    例

    例1 ArrayIterator::next() の例

    <?php
    $arrayobject     = new ArrayObject();

    $arrayobject[] = 'zero';
    $arrayobject[] = 'one';

    $iterator = $arrayobject->getIterator();

    while(    $iterator->valid()) {
    echo     $iterator->key() . ' => ' . $iterator->current() . "\n";

    $iterator->next();
    }
    ?>

    上の例の出力は以下となります。

    0 => zero
1 => one

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    User Contributed Notes 1 note

    up
    1
    onelsonsenna at gmail dot com
    13 years ago
    If you use exchangeArray method of ArrayObject and then next method of ArrayIterator like this:

    <?php

    $fruits     = array("apple", "grape", "lemon");

    $colors = array("blue", "yellow", "green");

    $arrayObject = new ArrayObject($fruits);

    $arrayIterator = $arrayObject->getIterator();

    while(    $arrayIterator->valid()) {

    if (    $arrayIterator->current() == "grape") {
    $arrayObject->exchangeArray($colors);
    }

    $arrayIterator->next();
    }

    ?>

    You will receive:

    PHP Notice: ArrayIterator::next(): Array was modified outside object and internal position is no longer valid

    So be careful with next and prev operations. :)
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