ArrayObject::getArrayCopy
(PHP 5, PHP 7, PHP 8)
ArrayObject::getArrayCopy — ArrayObject のコピーを作成する
パラメータ
この関数にはパラメータはありません。
戻り値
配列のコピーを返します。ArrayObject がオブジェクトを参照している場合は、 オブジェクトのプロパティの配列を返します。
例
例1 ArrayObject::getArrayCopy() の例
<?php
// フルーツの配列
$fruits = array("lemons" => 1, "oranges" => 4, "bananas" => 5, "apples" => 10);
$fruitsArrayObject = new ArrayObject($fruits);
$fruitsArrayObject['pears'] = 4;
// 配列のコピーを作成します
$copy = $fruitsArrayObject->getArrayCopy();
print_r($copy);
?>
上の例の出力は以下となります。
Array ( [lemons] => 1 [oranges] => 4 [bananas] => 5 [apples] => 10 [pears] => 4 )
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User Contributed Notes 5 notes
spidgorny at gmail dot com ¶
8 years ago
<?php
$data = $likeArray->getArrayCopy();
?>
will NOT be magically called if you cast to array. Although I've expected it.
<?php
$nothing = (array)$likeArray;
?>
Here, $data != $nothing.
Ivo von Putzer ¶
13 years ago
If you did something like this to make your constructor multidimensional capable you will have some trouble using getArrayCopy to get a plain array straight out of the method:
<?php
public function __construct( $array = array(), $flags = 2 )
{
// let’s give the objects the right and not the inherited name
$class = get_class($this);
foreach($array as $offset => $value)
$this->offsetSet($offset, is_array($value) ? new $class($value) : $value);
$this->setFlags($flags);
}
?>
That’s the way I solved it:
<?php
public function getArray($recursion = false)
{
// just in case the object might be multidimensional
if ( $this === true)
return $this->getArrayCopy();
return array_map( function($item){
return is_object($item) ? $item->getArray(true) : $item;
}, $this->getArrayCopy() );
}
?>
Hope this was useful!
jlshor at buffalo dot edu ¶
8 years ago
Is there a difference between casting to an array and using this function?
For instance, if we have:
$arrayObject = new ArrayObject([1, 2, 3]);
Is there a difference between these:
$array = (array) $arrayObject;
vs
$array = $arrayObject->getArrayCopy();
If not, is there any scenario where they would produce different results, or do they produce the result in different ways?
php at webflips dot net ¶
10 years ago
"When the ArrayObject refers to an object an array of the public properties of that object will be returned."
This description does not seem to be right:
<?php
class A
{
public $var = 'var';
protected $foo = 'foo';
private $bar = 'bar';
}
$o = new ArrayObject(new A());
var_dump($o->getArrayCopy());
/*
Dumps:
array(3) {
["var"]=>
string(3) "var"
["*foo"]=>
string(3) "foo"
["Abar"]=>
string(3) "bar"
}
*/
?>
So it does not only include the public properties.
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