ctype_space
(PHP 4 >= 4.0.4, PHP 5, PHP 7, PHP 8)
ctype_space — 空白文字かどうか調べる
パラメータ
戻り値
text
のすべての文字がなんらかの空白文字を
生成する場合に true
、そうでない場合に false
を返します。
空白文字には、タブ・垂直タブ・改行・復帰・フォームフィード文字も
含まれます。
空文字列を渡して呼び出した場合、結果は常に false
になります。
例
例1 ctype_space() の例
<?php
$strings = array(
'string1' => "\n\r\t",
'string2' => "\narf12",
'string3' => '\n\r\t' // 単一引用符に注意してください。
);
foreach ($strings as $name => $testcase) {
if (ctype_space($testcase)) {
echo "The string '$name' consists of whitespace characters only.\n";
} else {
echo "The string '$name' contains non-whitespace characters.\n";
}
}
?>
上の例の出力は以下となります。
The string 'string1' consists of whitespace characters only. The string 'string2' contains non-whitespace characters. The string 'string3' contains non-whitespace characters.
参考
- ctype_cntrl() - 制御文字かどうかを調べる
- ctype_graph() - 空白以外の印字可能な文字かどうかを調べる
- ctype_punct() - 空白、英数字以外の出力可能な文字かどうかを調べる
- IntlChar::isspace() - コードポイントが、スペース文字であるかを調べる
+add a note
User Contributed Notes 2 notes
gardnerjohng at hotmail dot com ¶
15 years ago
A function I wrote last night was fairly flexible in terms of detecting whitespace, and even took into account the pesky non-breaking spaces / zero-width spaces further up the Unicode alphabet.
The benefit here was being able to isolate and identify specific Unicode indices based on their subrange.
<?php
// Returns TRUE if the ASCII value of $string matches a registered whitespace character.
// * This includes non-breaking spaces, zero-width spaces, and any unicode values below 32.
// * $string: Character to identify. If string extends past one character, the value
// is truncated and only the initial character is examined.
function is_whitespace($string){
// Return FALSE if passed an empty string.
if($string == "") return FALSE;
$char = ord($string);
// Control Characters
if($char < 33) return TRUE;
if($char > 8191 && $char < 8208) return TRUE;
if($char > 8231 && $char < 8240) return TRUE;
// Additional Characters
switch($char){
case 160: // Non-Breaking Space
case 8287: // Medium Mathematical Space
return TRUE;
break;
}
return FALSE;
}
?>
vlabots at gmail dot com ¶
10 years ago
thanks to gardnerjohng, but a had some problems with non-breaking spaces in this function.
I added 2 more cases for this:
case 0xC2
case 0xA0
After this modification non-breaking spaces in my test code were successfully detected.
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