jddayofweek
(PHP 4, PHP 5, PHP 7, PHP 8)
jddayofweek — 曜日を返す
説明
曜日を返します。 モードに依存した文字あるいは整数を返す事が出来ます。
パラメータ
julian_day-
ユリウス積算日を表す整数値。
mode-
暦の曜日モード モード 意味 0 (デフォルト) 整数で曜日番号 (0=Sunday, 1=Monday, 等)を返します。 1 曜日(英グレゴリウス)を含む文字列を返します。 2 曜日の省略形(英グレゴリウス)を含む文字列を返します。
戻り値
グレゴリウス暦の曜日を表す数値あるいは文字列を返します。
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User Contributed Notes 1 note
kevind at communitycolor dot com ¶
7 years ago
You need to check to see how your client wants to represent the day of week. This function returns 0 for Sundays. ISO 8601 uses 7 for Sundays.
BTW, You can also calculate the day of week with modular division:
$dow = (1 + $julianday) % 7; // returns 0 for Sundays.
$dow = ($julianday % 7) + 1; // returns 7 for Sundays.
https://en.wikipedia.org/wiki/Julian_day#Finding_day_of_week_given_Julian_day_number
To make matters confusing. The Julian Date starts at noon UTC. Some programs such as SQLITE3 use real numbers to record date and time. If you pass this function a float; it will return a different day of week for the morning than for the afternoon.
When given a julianday with a decimal part you will need to add a half day and may need further adjustment for your timezone.
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