SQLite3::query
(PHP 5 >= 5.3.0, PHP 7, PHP 8)
SQLite3::query — SQL クエリを実行する
説明
SQL クエリを実行し、SQLite3Result オブジェクトを返します。 クエリが(DML文のように)結果を生成しない場合は、 返される SQLite3Result オブジェクトは役に立ちません。 そのようなクエリでは、SQLite3::exec() を代わりに使ってください。
パラメータ
query
-
実行したい SQL クエリ。
戻り値
SQLite3Result オブジェクトを返します。
失敗した場合に false
を返します
例
例1 SQLite3::query() の例
<?php
$db = new SQLite3('mysqlitedb.db');
$results = $db->query('SELECT bar FROM foo');
while ($row = $results->fetchArray()) {
var_dump($row);
}
?>
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User Contributed Notes 2 notes
bohwaz ¶
11 years ago
The recommended way to do a SQLite3 query is to use a statement. For a table creation, a query might be fine (and easier) but for an insert, update or select, you should really use a statement, it's really easier and safer as SQLite will escape your parameters according to their type. SQLite will also use less memory than if you created the whole query by yourself. Example:
<?php
$db = new SQLite3;
$statement = $db->prepare('SELECT * FROM table WHERE id = :id;');
$statement->bindValue(':id', $id);
$result = $statement->execute();
?>
You can also re-use a statement and change its parameters, just do $statement->reset(). Finally don't forget to close a statement when you don't need it anymore as it will free some memory.
paule-panke at example dot com ¶
7 years ago
Check with SQLite3Result::numColumns() for an empty result before calling SQLite3Result::fetchArray().
In contrast to the documentation SQLite3::query() always returns a SQLite3Result instance, not only for queries returning rows (SELECT, EXPLAIN). Each time SQLite3Result::fetchArray() is called on a result from a result-less query internally the query is executed again, which will most probably break your application.
For a framwork or API it's not possible to know in before whether or not a query will return rows (SQLite3 supports multi-statement queries). Therefore the argument "Don't execute query('CREATE ...')" is not valid.
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