PHPのお勉強!

PHP TOP

SQLite3Result::fetchArray

(PHP 5 >= 5.3.0, PHP 7, PHP 8)

SQLite3Result::fetchArray 結果の行を、連想配列あるいは数値添字配列あるいはその両方で取得する

説明

public SQLite3Result::fetchArray(int $mode = SQLITE3_BOTH): array|false

結果の行を、連想配列あるいは数値添字配列あるいはその両方で取得します。 デフォルトでは両方で取得します。

パラメータ

mode

次の行をどのように返すかを制御します。値は SQLITE3_ASSOCSQLITE3_NUMSQLITE3_BOTH のいずれかでなければなりません。

  • SQLITE3_ASSOC: 返された結果セットのカラム名をインデックスとする配列を返します。

  • SQLITE3_NUM: 返された結果セットのカラム番号をインデックスとする配列を返します。 カラム番号は 0 から始まります。

  • SQLITE3_BOTH: 返された結果セットのカラム名とカラム番号の両方をインデックスとする配列を返します。 カラム番号は 0 から始まります。

戻り値

結果の行を、連想配列あるいは数値添字配列あるいはその両方で取得します。 行がない場合は false を返します。

返される配列の値の型は、SQLite3 のデータ型と以下のようにマッピングされます: 数値型の場合、PHP_INT_MIN..PHP_INT_MAX の範囲に入れば、int にマッピングされます。そうでなければ、 string になります。Float 型は float に、 NULL 値は null に、 そして文字列型や Blob 型は string にマップされます。

add a note

User Contributed Notes 4 notes

up
18
Jason
10 years ago
Would just like to point out for clarification that each call to fetchArray() returns the next result from SQLite3Result in an array, until there are no more results, whereupon the next fetchArray() call will return false.

HOWEVER an additional call of fetchArray() at this point will reset back to the beginning of the result set and once again return the first result. This does not seem to explicitly documented, and caused me my own fair share of headaches for a while until I figured it out.

For example:

<?php
$returned_set
= $database->query("select query or whatever");

//Lets say the query returned 3 results
//Normally the following while loop would run 3 times then, as $result wouldn't be false until the fourth call to fetchArray()
while($result = $returned_set->fetchArray()) {
//HOWEVER HAVING AN ADDITIONAL CALL IN THE LOOP WILL CAUSE THE LOOP TO RUN AGAIN
$returned_set->fetchArray();
}
?>

Basically, in the above code fetchArray will return:
1st call | 1st result from $returned_set (fetchArray() call from while condition)
2nd call | 2nd result (fetchArray() call from while block)
3rd call | 3rd result (fetchArray() call from while condition)
4th call |FALSE (fetchArray() call from while block)
5th call | 1st result (fetchArray() call from while condition)
....

This will cause (at least in this case) the while loop to run infinitely.
up
11
paule-panke at example dot com
7 years ago
Check with SQLite3Result::numColumns() for an empty result before calling SQLite3Result::fetchArray().

In contrast to the documentation SQLite3::query() always returns a SQLite3Result instance, not only for queries returning rows (SELECT, EXPLAIN). Each time SQLite3Result::fetchArray() is called on a result from a result-less query internally the query is executed again, which will most probably break your application.
For a framwork or API it's not possible to know in before whether or not a query will return rows (SQLite3 supports multi-statement queries). Therefore the argument "Don't execute query('CREATE ...')" is not valid.
up
2
alan at synergymx dot com
14 years ago
To loop through a record set:

<?php
$db
= new SQLite3('auth.sqlite');

$sql = "SELECT user_id, username, opt_status FROM tbl_user";

$result = $db->query($sql);//->fetchArray(SQLITE3_ASSOC);

$row = array();

$i = 0;

while(
$res = $result->fetchArray(SQLITE3_ASSOC)){

if(!isset(
$res['user_id'])) continue;

$row[$i]['user_id'] = $res['user_id'];
$row[$i]['username'] = $res['username'];
$row[$i]['opt_status'] = $res['opt_status'];

$i++;

}

print_r($row);
?>
up
0
ghaith at cubicf dot net
7 years ago
// Open a new sqlite3 DB

$db = new SQLite3('./DB_EHLH.db');

// select all information from table "algorithm"

$results= $db->query("select * from algorithm");

//Create array to keep all results
$data= array();

// Fetch Associated Array (1 for SQLITE3_ASSOC)
while ($res= $results->fetchArray(1))
{
//insert row into array
array_push($data, $res);

}

//you can return a JSON array
echo json_encode($data);

//the output is a s follows
[
{"id":1,"algorithm":"GA"},
{"id":2,"algorithm":"PSO"},
{"id":3,"algorithm":"IWO"},
{"id":4,"algorithm":"OIWO"}
]
To Top