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    strval

    (PHP 4, PHP 5, PHP 7, PHP 8)

    strval — 変数の文字列としての値を取得する

    説明

    strval(mixed $value): string

    value の string としての値を 返します。文字列への変換の詳細については、string の ドキュメントを参照ください。

    この関数は、戻り値の書式設定は行いません。数値を文字列形式で書式設定したい場合は sprintf() あるいは number_format() を参照ください。

    パラメータ

    value

    文字列に変換したい変数。

    value には、任意のスカラー型、null および __toString() メソッドを実装した object を使うこともできます。 strval() は配列に対して使うことはできず、 __toString() メソッドを実装していないオブジェクトに対しても使うことはできません。

    戻り値

    value の文字列値を返します。

    例

    例1 マジックメソッド __toString() を使う strval() の例

    <?php
    class StrValTest
    {
    public function     __toString()
    {
    return     __CLASS__;
    }
    }

    // 'StrValTest' と表示します
    echo strval(new StrValTest);
    ?>

    参考

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    User Contributed Notes 7 notes

    up
    19
    Mark Clements
    8 years ago
    Some notes about how this function has changed over time, with regards the following statement:

    > You cannot use strval() on arrays or on objects that
    > do not implement the __toString() method.

    == Arrays ==

    In PHP 5.3 and below, strval(array(1, 2, 3)) would return the string "Array" without any sort of error occurring.

    From 5.4 and above, the return value is unchanged but you will now get a notice-level error: "Array to string conversion".

    == Objects ==

    For objects that do not implement __toString(), the behaviour has varied:

    PHP 4: "Object"
    PHP 5 < 5.2: "Object id #1" (number obviously varies)
    PHP >= 5.2: Catchable fatal error: Object of class X could not be converted to string
    up
    17
    Hayley Watson
    17 years ago
    As of PHP 5.2, strval() will return the string value of an object, calling its __toString() method to determine what that value is.
    up
    19
    Tom Nicholson
    20 years ago
    If you want to convert an integer into an English word string, eg. 29 -> twenty-nine, then here's a function to do it.

    Note on use of fmod()
    I used the floating point fmod() in preference to the % operator, because % converts the operands to int, corrupting values outside of the range [-2147483648, 2147483647]

    I haven't bothered with "billion" because the word means 10e9 or 10e12 depending who you ask.

    The function returns '#' if the argument does not represent a whole number.

    <?php
    $nwords     = array( "zero", "one", "two", "three", "four", "five", "six", "seven",
    "eight", "nine", "ten", "eleven", "twelve", "thirteen",
    "fourteen", "fifteen", "sixteen", "seventeen", "eighteen",
    "nineteen", "twenty", 30 => "thirty", 40 => "forty",
    50 => "fifty", 60 => "sixty", 70 => "seventy", 80 => "eighty",
    90 => "ninety" );

    function     int_to_words($x) {
    global     $nwords;

    if(!    is_numeric($x))
    $w = '#';
    else if(    fmod($x, 1) != 0)
    $w = '#';
    else {
    if(    $x < 0) {
    $w = 'minus ';
    $x = -$x;
    } else
    $w = '';
    // ... now $x is a non-negative integer.

    if($x < 21) // 0 to 20
    $w .= $nwords[$x];
    else if(    $x < 100) { // 21 to 99
    $w .= $nwords[10 * floor($x/10)];
    $r = fmod($x, 10);
    if(    $r > 0)
    $w .= '-'. $nwords[$r];
    } else if(    $x < 1000) { // 100 to 999
    $w .= $nwords[floor($x/100)] .' hundred';
    $r = fmod($x, 100);
    if(    $r > 0)
    $w .= ' and '. int_to_words($r);
    } else if(    $x < 1000000) { // 1000 to 999999
    $w .= int_to_words(floor($x/1000)) .' thousand';
    $r = fmod($x, 1000);
    if(    $r > 0) {
    $w .= ' ';
    if(    $r < 100)
    $w .= 'and ';
    $w .= int_to_words($r);
    }
    } else {     // millions
    $w .= int_to_words(floor($x/1000000)) .' million';
    $r = fmod($x, 1000000);
    if(    $r > 0) {
    $w .= ' ';
    if(    $r < 100)
    $word .= 'and ';
    $w .= int_to_words($r);
    }
    }
    }
    return     $w;
    }

    ?>

    Usage:
    <?php
    echo 'There are currently '. int_to_words($count) . ' members logged on.';
    ?>
    up
    13
    php at ianco dot co dot uk
    19 years ago
    I can't help being surprised that

    (string)"0" == (string)"0.00"

    evaluates to true. It's the same with strval and single quotes.
    === avoids it.

    Why does it matter? One of my suppliers, unbelievably, uses 0 to mean standard discount and 0.00 to mean no discount in their stock files.
    up
    9
    kendsnyder+phpnet at gmail dot com
    17 years ago
    The only way to convert a large float to a string is to use printf('%0.0f',$float); instead of strval($float); (php 5.1.4).

    // strval() will lose digits around pow(2,45);
    echo pow(2,50); // 1.1258999068426E+015
    echo (string)pow(2,50); // 1.1258999068426E+015
    echo strval(pow(2,50)); // 1.1258999068426E+015

    // full conversion
    printf('%0.0f',pow(2,50)); // 112589906846624
    echo sprintf('%0.0f',pow(2,50)); // 112589906846624
    up
    -1
    NyctoFixer at gmail dot com
    17 years ago
    As of PHP 5.1.4 (I have not tested it in later versions), the strval function does not attempt to invoke the __toString method when it encounters an object. This simple wrapper function will handle this circumstance for you:

    <?

    /**
    * Returns the string value of a variable
    *
    * This differs from strval in that it invokes __toString if an object is given
    * and the object has that method
    */
    function stringVal ($value)
    {
    // We use get_class_methods instead of method_exists to ensure that __toString is a public method
    if (is_object($value) && in_array("__toString", get_class_methods($value)))
    return strval($value->__toString());
    else
    return strval($value);
    }

    ?>
    up
    -1
    Steve Ball
    19 years ago
    It seems that one is being treated as an unsigned large int (32 bit), and the other as a signed large int (which has rolled over/under).

    2326201276 - (-1968766020) = 4294967296.
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