mysqli_result::fetch_all
mysqli_fetch_all
(PHP 5 >= 5.3.0, PHP 7, PHP 8)
mysqli_result::fetch_all -- mysqli_fetch_all — 結果のすべての行を連想配列・数値添字配列あるいはその両方の形式で取得する
説明
オブジェクト指向型
手続き型
すべての結果の行を取得し、その結果セットを 連想配列・数値添字配列あるいはその両方の二次元配列で返します。
注意:
PHP 8.1.0 より前のバージョンでは、 この関数は mysqlnd でのみ利用可能でした。
パラメータ
result
-
手続き型のみ: mysqli_query()、mysqli_store_result()、mysqli_use_result()、mysqli_stmt_get_result() が返す mysqli_result オブジェクト。
mode
-
このオプションは、 結果の行データから返す配列の型を指定します。ここで指定可能な値は 定数
MYSQLI_ASSOC
、MYSQLI_NUM
あるいはMYSQLI_BOTH
. のいずれかです。
戻り値
結果の行を含む連想配列あるいは数値添字配列の配列を返します。
変更履歴
バージョン | 説明 |
---|---|
8.1.0 | libmysqlclient をリンクしている場合でも、 この関数を使えるようになりました。 |
例
例1 mysqli_result::fetch_all() の例
オブジェクト指向型
<?php
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");
$result = $mysqli->query("SELECT Name, CountryCode FROM City ORDER BY ID LIMIT 3");
$rows = $result->fetch_all(MYSQLI_ASSOC);
foreach ($rows as $row) {
printf("%s (%s)\n", $row["Name"], $row["CountryCode"]);
}
手続き型
<?php
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$mysqli = mysqli_connect("localhost", "my_user", "my_password", "world");
$result = mysqli_query($mysqli, "SELECT Name, CountryCode FROM City ORDER BY ID LIMIT 3");
$rows = mysqli_fetch_all($result, MYSQLI_ASSOC);
foreach ($rows as $row) {
printf("%s (%s)\n", $row["Name"], $row["CountryCode"]);
}
上の例の出力は以下となります。
Kabul (AFG) Qandahar (AFG) Herat (AFG)
参考
- mysqli_fetch_array() - 結果セットの次の行を連想配列・数値添字配列あるいはその両方の形式で取得する
- mysqli_fetch_column() - 結果セットの次の行から、単一のカラムの値を取得する
- mysqli_query() - データベース上でクエリを実行する
+add a note
User Contributed Notes 5 notes
jcastro at eftec dot cl ¶
9 years ago
I tested using "fetch all" versus "while / fetch array" and :
fetch-all uses less memory (but not for so much).
In my case (test1 and test2): 147008,262848 bytes (fetch-all) versus 147112,262888 bytes (fetch-array & while.
So, about the memory, in both cases are the same.
However, about the performance
My test takes :350ms (worst case) using fetch-all, while it takes 464ms (worst case) using fetch-array, or about 35% worst using fetch array and a while cycle.
So, using fetch-all, for a normal code that returns a moderate amount of information is :
a) cleaner (a single line of code)
b) uses less memory (about 0.01% less)
c) faster.
php 5.6 32bits, windows 8.1 64bits
darek334 at gazeta dot pl ¶
1 year ago
be careful fetch_all(MYSQLI_ASSOC ) returns an array in the form
<?php
array(0 => array(...row...), 1 => array(...row...) .... ), even if is one row...
?>
not compared to fetch_assoc() which returns one array of the result in form:
<?php
array(...row...)
?>
mail2magvay at rambler dot ru ¶
5 years ago
By the way, this case pretty work's too:
$services = $mysqli->query("SELECT * FROM table1");
if($services && $services->num_rows>0){
$services->fetch_all(MYSQLI_ASSOC);
}
foreach($services as $service){
echo $service; //work properly, cause it implements Iterator
}
That's mean in this case $services is a valid array (or empty array)
m dot amiot at otak-arts dot com ¶
12 years ago
If you really need this function, you can just extend the mysqli_result class with a function like this one.
<?php
public function fetch_all($resulttype = MYSQLI_NUM)
{
if (method_exists('mysqli_result', 'fetch_all')) # Compatibility layer with PHP < 5.3
$res = parent::fetch_all($resulttype);
else
for ($res = array(); $tmp = $this->fetch_array($resulttype);) $res[] = $tmp;
return $res;
}
?>
andrey at php dot net ¶
14 years ago
Return value changed in 5.3.3 - between 5.3.0 and 5.3.2 (incl.) when the result set was empty NULL was returned. 5.3.3+ returns an empty array.
Also, mysqli_fetch_all works only for buffered result sets, which are the default for mysqli_query. MYSQLI_USE_RESULT will be supported in 5.3.4+
However, it makes little sense to use it this way, materialising unbuffered sets. In this case choose STORE_RESULT, and fetch_all won't copy the data, but reference it, as it is stored already in mysqlnd.
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